Given an array of strings, return all groups of strings that are anagrams.

Note: All inputs will be in lower-case.

这道题的意思是返回含有相同字母的字符串

First, I don't know the real meaning of this problem. Next ,After searching the answer through Internet,I also feel puzzled.

Last, I have no experience about the function of HashMap or Hashtable.

I feel exhausted about the current of my attitude. Anyway What I should do is try my best.

Fighting!

慢慢积累

char[] aChar = a.toCharArray();

add是将传入的参数作为当前List中的一个Item存储，即使你传入一个List也只会另当前的List增加1个元素，而addAll是传入一个List，将此List中的所有元素加入到当前List中，也就是当前List会增加的元素个数为传入的List的大小

不多说了，今天要再刷3道题，然后写论文！

下面附上代码：

public List
     
       anagrams(String[] strs) {               ArrayList
      
        result = new ArrayList
       
        ();        HashMap
        
         > ht = new HashMap
         
          >();        for(int i =0;i
          
            val = ht.get(sor); if(val!=null){ val.add(strs[i]); } else{ val = new ArrayList
           
            (); val.add(strs[i]); ht.put(sor,val); } } Set
            
              set = ht.keySet(); for(String s : set){ ArrayList
             
               val = ht.get(s); if(val.size()>1){ result.addAll(val); } } return result; } public String sorted(String a){ char[] aChar = a.toCharArray(); Arrays.sort(aChar); return new String(aChar); }